Schedule of column and footing
Sr.
No.
|
Column no.
|
Footing size
|
Footing reinforcement
|
D/d
(depth)
|
Below plinth/column
|
Stilt floor column
|
First floor
|
Second floor
|
Rings/stirrups
|
1.
|
C1,C2,C3
|
2.8 x 2.8
|
Ф 16 @ 150 c/c
|
0.8
|
0.3 x 0.9
|
0.3 x 0.800
|
0.3 x 0.750
|
0.23 x 0.600
|
Ф 8 @ 100 c/c
|
2.
|
C4,C5,C6
|
2.6 x 2.8
|
Ф 20 @ 200 c/c
|
0.6
|
0.3 x 0.8
|
0.3 x 0.8
|
0.3 x 0.75
|
0.3 x 0.700
|
Ф 8 @ 100 c/c
|
3.
|
C7,C8,C9,C10,C11
|
3.2 x 3.2
|
Ф 25 @ 250 c/c
|
0.9
|
0.3 x 1
|
0.3 x 0.9
|
0.3 x 0.850
|
0.3 x 0.700
|
Ф 12 @ 175 c/c
|
4.
|
C12,C13,C14
|
2.2 x 2.5
|
Ф 20 @ 175 c/c
|
0.7
|
0.3 x 0.750
|
0.3 x 0.700
|
0.3 x 0.650
|
0.3 x 0.600
|
Ф 8 @ 100 c/c
|
5.
|
C15,C16
|
1.6 x 1.6
|
Ф 12 @ 125 c/c
|
0.6
|
0.23 x 0.600
|
0.23 x 0.550
|
0.23 x 0.500
|
0.20 x 0.475
|
Ф 10 @ 125 c/c
|
Footing no. 1,2,3
Footing size = 2.8 x 2.8 Footing column size = 0.3 x 0.9
Depth of footing = 0.8
Footing reinforcement
16 diameter @ 150 c/c (Bothway)
Footing column stirrups 8 diameter @ 100 c/c
Main bar steel 16 diameter 8 nos.
Main bar steel 16 dia. 8 nos.
3 + 40 d
3 + 40 x 16
3.64 meter
16 dia. 8 nos. = 3.64 x 8 = 29.12 meter
Stirrups 8 dia. 100 c/c
546.66 + 546.66 + 220 + 220 – 5 d + 10 d + 10 d
1533.32 – 5 x 8 mm + 10 x 8 mm + 10 x 8 mm
1653.32
1.65 meter
No. of stirrups = length of bar / c/c distance between the stirrups
Therefore, no. of stirrups = 3.64 / 100 mm
3.64 / 0.100 meter
36.4 say 37 meter add one extra bar
i.e. 38 meter
8 dia. Bar = 1.65 x 38 = 62.7 meter
For 2 rings
62.7 x 2 no. bar rings
= 125.4 meter
Master rings 8 dia. @ 100 c/c
820 + 820 + 220 + 220 – 5 d + 10 d + 10 d
2080 – 5 x 8 mm + 10 x 8 mm + 10 x 8 mm
2200
2.2 meter
No. of stirrups = length of bar / c/c distance between the stirrups
Therefore, no. of stirrups = 3.64 / 100 mm
3.64 / 0.100
36.4 say 37 add one extra bar
i.e 38 meter
8 dia. = 2.2 x 38 = 83.6 meter
Footing reinforcement 16 dia. @ 150 c/c
No. of bars = 2.8 /0.150 = 18.66 say 19
One bar length = L + 10 d + 10 d – 40 – 40 ….(Deduct 40mm cover from both end)
= 2.8 + 10 x 16 mm + 10 x 16 mm – 40 – 40
= 3.04 meter
Therefore, 16 dia. Bar = 3.04 x 19 = 57.76 meter
For bothway
57.76 x 2
16 dia. Bar = 115.52 meter
Footing no. 4,5,6
Footing size = 2.6 x 2.8 Footing column size = 0.3 x 0.8
Depth of footing = 0.6
Footing reinforcement
20 diameter @ 200 c/c (Bothway)
Footing column stirrups 8 diameter @ 100 c/c
Main bar steel 16 diameter 8 nos.
Main bar steel 16 dia. 8 nos. (Footing column)
3 + 40 d
3 + 40 x 16
3.64 meter
16 dia. 8 nos. = 3.64 x 8 = 29.12 meter
Stirrups 8 dia. 100 c/c
480 + 480 + 220 + 220 – 5 d + 10 d + 10 d
1400 – 5 x 8 mm + 10 x 8 mm + 10 x 8 mm
1520
1.52 meter
No. of stirrups = length of bar / c/c distance between the stirrups
Therefore, no. of stirrups = 3.64 / 100 mm
3.64 / 0.100 meter
36.4 say 37 meter add one extra bar
i.e. 38 meter
8 dia. Bar = 1.52 x 38 = 57.76 meter
For 2 rings
57.76 x 2 no. bar rings
= 115.52 meter
Master rings 8 dia. @ 100 c/c
720 + 720 + 220 + 220 – 5 d + 10 d + 10 d
1880 – 5 x 8 mm + 10 x 8 mm + 10 x 8 mm
2000
2 meter
No. of stirrups = length of bar / c/c distance between the stirrups
Therefore, no. of stirrups = 3.64 / 100 mm
3.64 / 0.100
36.4 say 37 add one extra bar
i.e 38 meter
8 dia. = 2 x 38 = 76 meter
Footing reinforcement 20 dia. @ 200 c/c
No. of bars = 2.8 /0.200 = 14
One bar length = L + 10 d + 10 d – 40 – 40 ….(Deduct 40mm cover from both end)
= 2.6 + 10 x 20 mm + 10 x 20 mm – 40 – 40
= 2.92 meter
Therefore, 20 dia. Bar = 2.92 x 14 = 40.88 meter
No. of bar = 2.6 / 0.200 = 13
One bar length = L + 10 d + 10 d – 40 – 40
= 2.8 + 10 x 20 mm + 10 x 20 mm – 40 – 40
= 3.12 meter
20 dia. Bar = 3.12 x 13 = 40.56 meter
Total length of 20 dia. Bar = 40.88 + 40.56 = 81.44 meter
Footing no. 7,8,9,10,11
Footing size = 3.2 x 3.2 Footing column size = 0.3 x 1
Depth of footing = 0.9
Footing reinforcement
25 diameter @ 250 c/c (Bothway)
Footing column stirrups 12 diameter @ 175 c/c
Main bar steel 25 diameter 8 nos.
Main bar steel 25 dia. 8 nos.
3 + 40 d
3 + 40 x 25 mm
4 meter
25 dia. 8 nos. = 4 x 8 = 32 meter
Stirrups 12 dia. 175 c/c
666.66 + 666.66 + 220 + 220 – 5 d + 10 d + 10 d
1773.32 – 5 x 8 mm + 10 x 8 mm + 10 x 8 mm
1953.32
1.95 meter
No. of stirrups = length of bar / c/c distance between the stirrups
Therefore, no. of stirrups = 4 / 175 mm
4 / 0.175 meter
22.85 say 23 meter add one extra bar
i.e. 24
12 dia. Bar = 1.95 x 24 = 46.8 meter
For 2 rings
46.8 x 2 no. bar rings
= 93.6 meter
Master rings 12 dia. @ 175 c/c
999.99 + 999.99 + 220 + 220 – 5 d + 10 d + 10 d
2439.98 – 5 x 12 mm + 10 x 12 mm + 10 x 12 mm
2619.98
2.61 meter
No. of stirrups = length of bar / c/c distance between the stirrups
Therefore, no. of stirrups = 4 / 175 mm
4 / 0.175
22.85 say 23 add one extra bar
i.e 24
12 dia. = 2.61 x 24 = 62.64 meter
Footing reinforcement 25 dia. @ 250 c/c
No. of bars = 3.2 /0.250 = 12.8 say 13
One bar length = L + 10 d + 10 d – 40 – 40 ….(Deduct 40mm cover from both end)
= 3.2 + 10 x 25 mm + 10 x 25 mm – 40 – 40
= 3.6 meter
Therefore, 25 dia. Bar = 3.6 x 13 = 47.06 meter
For bothway
47.06 x 2
25 dia. Bar = 94.12 meter
Footing no. 12,13,14
Footing size = 2.2 x 2.5 Footing column size = 0.3 x 0.75
Depth of footing = 0.7
Footing reinforcement
20 diameter @ 175 c/c (Bothway)
Footing column stirrups 8 diameter @ 100 c/c
Main bar steel 20 diameter 8 nos.
Main bar steel 20 dia. 8 nos. (Footing column)
3 + 40 d
3 + 40 x 20
3.8 meter
20 dia. 8 nos. = 3.8 x 8 = 30.4 meter
Stirrups 8 dia. 100 c/c
500 + 500 + 220 + 220 – 5 d + 10 d + 10 d
1440 – 5 x 8 mm + 10 x 8 mm + 10 x 8 mm
1560
1.56 meter
No. of stirrups = length of bar / c/c distance between the stirrups
Therefore, no. of stirrups = 3.8 / 100 mm
3.8 / 0.100 meter
38 add one extra bar
i.e. 39
8 dia. Bar = 1.56 x 39 = 60.84 meter
For 2 rings
60.84 x 2 no. bar rings
8 dia. Bar = 121.68 meter
Master rings 8 dia. @ 100 c/c
670 + 670 + 220 + 220 – 5 d + 10 d + 10 d
1780 – 5 x 8 mm + 10 x 8 mm + 10 x 8 mm
1900
1.9 meter
Master rings 8 dia.
No. of stirrups = length of bar / c/c distance between the stirrups
Therefore, no. of stirrups = 3.8 / 100 mm
3.8 / 0.100
38 add one extra bar
i.e 39
8 dia. = 1.9 x 39 = 74.1 meter
Footing reinforcement 20 dia. @ 175 c/c
No. of bars = 2.5 /0.175 = 14
One bar length = L + 10 d + 10 d – 40 – 40 ….(Deduct 40mm cover from both end)
= 2.2 + 10 x 20 mm + 10 x 20 mm – 40 – 40
= 2.52 meter
Therefore, 20 dia. Bar = 2.52 x 15 = 37.8 meter
No. of bar = 2.2 / 0.175 = 12.57 say 13
One bar length = L + 10 d + 10 d – 40 – 40
= 2.5 + 10 x 20 mm + 10 x 20 mm – 40 – 40
= 2.82 meter
20 dia. Bar = 2.82 x 13 = 36.66 meter
Total length of 20 dia. Bar = 37.8 + 36.66 = 74.46 meter
Footing no. 15,16
Footing size = 1.6 x 1.6 Footing column size = 0.23 x 0.600
Depth of footing = 0.6
Footing reinforcement
12 diameter @ 225 c/c (Bothway)
Footing column stirrups 10 diameter @ 125 c/c
Main bar steel 32 diameter 8 nos.
Main bar steel 32 dia. 8 nos.
3 + 40 d
3 + 40 x 32 mm
4.28 meter
32 dia. 8 nos. = 4.28 x 8 = 34.24 meter
Stirrups 10 dia. 125 c/c
346.66 + 346.66 + 150 + 150 – 5 d + 10 d + 10 d
993.32 – 5 x 10 mm + 10 x 10 mm + 10 x 10 mm
1143.32
1.14 meter
No. of stirrups = length of bar / c/c distance between the stirrups
Therefore, no. of stirrups = 4.28 / 125 mm
4.28 / 0.125 meter
34.24 say 35 add one extra bar
i.e. 36
10 dia. Bar = 1.14 x 36 = 41.04 meter
For 2 rings
41.04 x 2 no. bar rings
= 82.08 meter
Master rings 10 dia. @ 125 c/c
520 + 520 + 150 + 150 – 5 d + 10 d + 10 d
1340 – 5 x 10 mm + 10 x 10 mm + 10 x 10 mm
1490
1.49 meter
No. of stirrups = length of bar / c/c distance between the stirrups
Therefore, no. of stirrups = 4.28 / 125 mm
4.28 / 0.125
34.24 say 35 add one extra bar
i.e 36
10 dia. = 1.49 x 36 = 58.11 meter
Footing reinforcement 12 dia. @ 225 c/c
No. of bars = 1.6 /0.225 = 7.11 say 8
One bar length = L + 10 d + 10 d – 40 – 40 ….(Deduct 40mm cover from both end)
= 1.6 + 10 x 12 mm + 10 x 12 mm – 40 – 40
= 1.76 meter
Therefore, 12 dia. Bar = 1.76 x 8 = 14.08 meter
For bothway 12 dia. bar
14.08 x 2
12 dia. Bar = 28.16 meter
