Example - Surveying Readings

station
Reading
R.L. of plane of Colimation (H.I.)
Reduced level
Remarks
Back sight
Inter site
Fore sight
A
0.422


482.345

B.M. 1 on the base of the pillar
B
1.285

0.684


Mech. lab
C
1.793

0.506



D

4.462



On parapet wall of a slab drain
E
3.120

2.416



F
1.234

1.517



G


1.232


B.M. 2 on parapet wall of old Railway bridge









Station A

H.I. – B.S. = R.L.

482.345 – 0.422 = 481.923


Station B

B.S. – F.S. + H.I.

1.285 – 0.684 + 482.345

= 482.946 (New H.I.)

New H.I. – B.S. = R.L.

482.946 – 1.285 = 481.661



Station C

B.S. – F.S. + H.I.

1.793 – 0.506 + 482.546

New H.I. – B.S. = R.L.

484.233 – 4.462 = 475.711


Station D

B.S. – F.S. + H.I.

3.120 – 2.416 + 484.233

= 484.937  (New H.I.)

New H.I. – B.S. = R.L.

484.937 – 3.120 = 481.817


Station F

B.S. – F.S. + H.I.

1.234 – 1.517 + 484.937

= 484.654 (New H.I.)

New H.I. – B.S. = R.L.

484.654 – 1.234 = 483.420


Station G

H.I. – F.S. = R.L.

484.654 – 1.232 = 483.422


Result -

station
Reading
R.L. of plane of Colimation (H.I.)
Reduced level
Remarks
Back sight
Inter site
Fore sight
A
0.422


482.345
481.923
B.M. 1 on the base of the pillar
B
1.285

0.684
482.946
481.661
Mech. lab
C
1.793

0.506
484.233
482.440

D

4.462


479.771
On parapet wall of a slab drain
E
3.120

2.416
484.937
481.817

F
1.234

1.517
484.657
483.420

G


1.232

483.422
B.M. 2 on parapet wall of old Railway bridge
Arithmetical
Check
7.854

6.355

+ 1.499

7.854 – 6.355  =
+ 1.499


Arithmetical Check –

The difference between the sum of the back sight & the sum of the foresights should be equals to the difference between the first & last reduced level.