How to calculate Volume of Retaining Wall? - Type II

Volume of Retaining Wall = Volume of A + Volume of B + Volume of C

Volume of A

= Length x Breadth x Height

= 12 x 4 x 0.4

= 19.2 m³

Volume of B

= { [(a + b) / 2] x h } x L

= { [(0.4 + 0.6) / 2] x 4 } x 12

= 24 m³

Volume of C

= { [(a + b) / 2] x h } x L

= { [(0.6 + 2) / 2] x 4 } x 0.4

= 2.08 m³

Number of walls is 2

Therefore , 2.08 x 2 no. of walls  = 4.16 m³

Total Volume of Retaining Wall

= 19.2 + 24 + 4.16

= 47.36 m³