How to make bar bending schedule of pile foundation?

VERTICAL BAR CALCULATION

Development length = 50 d

Steel

0 to -12 m	16-25 ф
-12 to -21m	16-20 ф
-21 to -30.5m	16-16 ф

Length of 1 bar 25 ф

= 50 d + 12000 + 50 d

= (50 x 25) + 12000 + (50 x 25)

= 14500 mm

= 14.5 m

Therefor,

Length for 16 no. bar = 14.5 x 16 = 232 m

Length of 1 bar 20 ф

= 9000 + 50 d

= 9000 + (50 x 20)

= 10000 mm

= 10 m

Therefor,

Length for 16 no. bar = 10 x 16 = 160 m

Length of 1 bar 16 ф

= 9500 + 300 – (bend)

= 9500 + 300 – (1 x 2 x d)

= 9500 + 300 – (1 x 2 x 16)

= 9768 mm

= 9.768 m

Therefor,

Length of 16 no. bar = 9.768 x 16 = 156.29 m

MASTER RING CALCULATION

Given:

Dia. Of master ring = 16 mm @ 1500 mm c/c

Length of pile = 30.5 m or 30500 mm

r = Radius of pile – clear cover – spiral ring dia. – vertical bar dia. – half of master ring dia.

r = 500 – 75 – 8 – 25 – (16/2)

r = 384 mm

r = 0.384 m

Length of 1 master ring = Circumference of circle

= 2 πr

= 2 x 3.14 x 0.384

= 2.4 m

Total no. of master ring = (Length of pile / Spacing) + 1

= (30500 / 1500) + 1

= 21 no.

For 24 nos. of master ring

= 2.4 x 21

= 50.4 m

SPIRAL RING CALCULATION

Given:

Pitch or Spacing = 150 mm

Clear cover = 75 mm

Dia. of pile = 1000 mm or 1 m

Length of pile = 30.5 m or 30500 mm

Dia. of spiral bar = 8 mm ф

Net radius of spiral in caging = radius of pile – clear cover – half of spiral bar dia.

= 500 – 75 – ( 8/2 )

= 500 – 75 – 4

r = 421 mm

Length of one spiral ring = circumference of one spiral ring

= 2 πr

= 2 x 3.14 x 421

= 2645 mm

= 2.645 m

No. of spirals = ( Length of pile / Pitch of pile ) + 1

= ( 30500 / 150 ) + 1

= 204 no.

Total length of spiral ring = 2.645 x 204 = 539.58 m

We know length of one full length bar is 12 m.

Lap considered  50 d

= 50 x 8

= 400 mm

= 0.4 m

Number of lap = [ Total no. of bar / One full length bar ] – 1

= [ 539.58 / 12 ] – 1

= 44 nos.

Total length of lap = 0.4 x 44 = 17.6 m

Total length of spiral ring = 539.58 + 17.6 = 557.18 m

Total weight of steel required for pile

Dia. of bar in mm	Total length in m	Unit weight of steel in kg/m	Total weight in kg
8 mm	557.18 m	0.395 kg/m	220 kg
16 mm	206.69 m	1.58 kg/m	326.6 kg
20 mm	160 m	2.47 kg/m	395.2 kg
25 mm	232 m	3.86 kg/m	895.5 kg

PILE CAP STEEL BAR CALCULATION

Explaination for finding a & b value

a = 1000 – 75 – 50 – 12.5 + 150

a = 1012.55 mm

a = 1.0125 m

b = 1000 – 50 – 6 + 150

b = 1094 mm

b = 1.094 m

PILE CAP ( 4200 x 4200 )

Clear cover = 50 mm

Bottom reinforcement 1^st layer

25 ф = Length of pile cap – ( 2 x clear cover ) – ( 2 x half of bar ) + (2 x a) – ( 2 x 2d )

25 ф = 4200 – ( 2 x 50 ) – ( 2 x 25/2 ) + ( 2 x 1012.5 ) – ( 2 x 2d )

= 6000 mm

= 6 m

Number of bar = [ Length of bar / Spacing ] + 1

= [ 4200 / 100 ] + 1

= 43 nos.

For 43 nos,

Total length of bar required = 6 x 43 = 258 m

Top reinforcement

12 ф = Length of pile cap – (2xclear cover) – (2xhalf of bar) + (2xb) – (2x2d)

12 ф = 4200 – ( 2 x 50 ) – ( 2 x 6 ) + ( 2 x 1094 ) – ( 2 x 2 x 12 )

= 6.228 m

Number of bar = [ Length of bar / Spacing ] + 1

= [ 4200 / 125 ] + 1

= 35 nos.

For 35 nos.

Total length of bar required = 6.228 x 35 = 218 m

PILE CAP ( 4200 x 2000 )

Explaination for finding value a¹ & b¹

a¹ = 1000 – 75 – 50 – 12.5 + 150

a¹ = 1012.55 mm

a¹ = 1.0125 m

b¹ = 1000 – 50 – 6 + 150

b¹ = 1094 mm

b¹ = 1.094 m

PILE CAP ( 4200 x 4200 )

Clear cover = 50 mm

Bottom reinforcement 2^st layer

25 ф = Length of pile cap – ( 2 x clear cover ) – ( 2 x half of bar ) + (2 x a¹) – ( 2 x 2d )

25 ф = 4200 – ( 2 x 50 ) – ( 2 x 12.5 ) + ( 2 x 987.5 ) – ( 2 x 2 x 25 )

= 5950 mm

= 5.95 m

Number of bar = [ Length of bar / Spacing ] + 1

= [ 4200 / 100 ] + 1

= 43 nos.

For 43 nos,

Total length of bar required = 5.95 x 43 = 255.85 m

Top reinforcement

12 ф = Length of pile cap – (2xclear cover) – (2xhalf of bar) + (2xb¹) – (2x2d)

12 ф = 4200 – ( 2 x 50 ) – ( 2 x 6 ) + ( 2 x 1082 ) – ( 2 x 2 x 12 )

= 6.204 m

Number of bar = [ Length of bar / Spacing ] + 1

= [ 4200 / 125 ] + 1

= 35 nos.

For 35 nos.

Total length of bar required = 6.204 x 35 = 217.14 m

SIDE FACE REINFORCEMENT

Explaination for a value a

a= 2100 – 50 – 6 + 150

a= 2194 mm

a= 2.194 m

12 ф = { Length of pile cap – ( 2 x clear cover ) – ( 2 x half of bar ) + (2xa) – (2 x 2d) } x 2

= { 4200 – (2x50) – ( 2 x 6 ) + ( 2 x 2194 ) – ( 2 x 2 x 12 ) } x 2

= 16.856 m

For 7 no. of bars

= 16.856 x 16

= 118 m

PILE CAP STEEL QUANTITY

Dia. in mm	Total length in m	Unit weight in kg	Total weight in kg
25 mm	513.85 m	3.86 kg	1983.4 kg
12 mm	553.14 m	0.889 kg	491.7 kg