The Board of Technical
Examinations intends to conduct an examination. The result is to be declared
within a period of 60 days. This activity can be shown by the following Bar
(Gantt) Chart.
First of all, it is necessary
to sort out the activities which are independent and interdependent and then to
decide the order of their sequence.
|
S.No.
|
Activity
|
Time
required
|
|
1.
|
Collection of examination forms and fees
|
10
days
|
|
2.
|
Setting of question papers
|
30
days
|
|
3.
|
Distribution of question papers and answer books
|
5
days
|
|
4.
|
Seating arrangements
|
5
days
|
|
5.
|
Collection of answer books and assessment work
|
20
days
|
|
6.
|
Preparation of mark sheets and declaration of result
|
10
days
|
In the above example, the
activities at serial numbers one and two are independent. Therefore, they can
be started independently, at the same time. The activities at serial numbers
three and four can also be taken up simultaneously. But the activity at number
five is dependent on the activities at serial numbers 1, 2, 3, and 4. It
cannot, therefore, be started unless the activities at serial numbers 1, 2, 3,
4 are completed. The time required if it is taken up earlier. Completion of
results of the last paper can taken 5 days. Thus, five days can be saved in
this way.
Following are the commonly
appearing situations along with bar chart given below:
|
S.No.
|
Situation
|
Bar Chart
|
Net work
|
|
1.
|
Activity ‘Q’ follows activity
‘P’
|
 |
 |
|
2.
|
Activity ‘Q’ can start at
same time as ‘P’ but not before it.
|
 |
 |
|
3.
|
Activity ‘R’ follows activity
‘P’ and ‘Q’
|
 |
 |
|
4.
|
Activities ‘Q’ and ‘R’ follow
‘P’
|
 |
 |
|
5.
|
Activities ‘R’ and ‘S’ follow
activity ‘P’ & ‘Q’
|
 |
 |
|
6.
|
Activity ‘R’ follows activity
‘P’ and activity ‘S’ follows activities ‘P’ and ‘Q’
|
 |
 |
0 Comments