A bridge pier consists of
following dimensions Top width = 1m, Height = 12m, Length = 8m, Side face batter
1 in 6. Assume end daces to be vertical. Find out the quantities of the
following items :
C.R. Masonry in pier.
Solution:
Section A and B are in the
triangular prism form,
Hence volume of A & B
= 2 (1/2 x 2 x 12 x 8)
= 192 cu.m.
Section C is in the form of
rectangular prism.
Hence volume of C
= 1 x 12 x 8
= 96 cu.m.
Therefor, Total volume of bridge
pier
= 192 + 96 cu.m.
= 288 cu.m.
Therefor, Quantity of CR
Masonry in the Bridge Pier = 288 Cu.m.
There are two battered surfaces
which have equal surface area. To find area of battered face, we have to
initially find the slant height which is equal to –
= 12.17 m.
Therefor, Total area battered
surface
= 2 (8 x 12.17)
= 194.72 Sq.m.
Therefor Qty of Cement pointing
to the battered faces
= 194.72 sq.m.