Calculate the quantity of materials required for foundation in P.C.C (1:4:8) 15 sq. meter

Proportion given = 1:4:8 let it be found to have about 45% voids then volume of dry materials required for one cubic of concrete would be: 1+0.45 Cu.m

Therefore

1 part cement = (1+0.45) / 1+4+8 = 0.111 cu,m,

Therefore

4 part fine aggregate =[ (1+0.45) / 1+4+8] x 4 = 0.446 cu.m.

Therefore

8 part coarse aggregate = [(1+0.45) / 1+4+8] x 8 = 0.892 cu.m.

Therefore

Cement required = 15 x 0.111 = 1.665 cu.m.

= 30 bags of cement reqd. for 1 cu.m.

No. of cement bag required = 50 bags

Therefore

Fine aggregate required = 15 x 0.446 = 6.69 cu.m.

Therefore

Coarse aggregate required = 15 x 0.892 = 13.38 cu.m.