Area of A
= L x B
= 3 x 2
= 6 m2
Area of B
= L x B
= 6 x 2
= 12 m2
Total Area = Area of A + Area of B
= 6 + 12
= 18 m2
Area of one tile = 600 mm x 600 mm
= 0.6 m x 0.6 m
= 0.36 m2
Therefor.
Number of tiles required = (Total Area / Area of tile)
= 18 / 0.36
= 50 no.
Consider wastage 5 % = 50 + [(5/100) x 50]
= 52.5 say 53 nos.