Moziace tile flooring
Size of tile = 20 cm x 20 cm
Thickness of lime base = 20 mm
Proportion of mortar = ( 1 : 2 : 4 )
Store room ( 2.20 meter x 3.00 meter )
Area of one tile = 20 cm x 20 cm
Area of one tile = 400 cm
Area of one tile = 0.04 m2
Therefore, no. of tiles required = 2.20 x 3.00 / 0.04
No. of tiles required = 6.6/0.04
No. of tiles required = 165 nos.
Proportion of mortar (1:2:4)
Thickness of lime base = 20 mm
Volume of lime base = Area of room x Thickness of lime base
Volume of lime base = 6.6 x (20mm/1000)……..(convert mm into meter)
Volume of lime base = 6.6 x 0.02
Volume of lime base = 0.132 m3 (cubic meter)
Considering 25 % more due to losses
= 0.132 + [0.132 x (25/100)]
= 0169 m3 (cubic meter)
Quantity of cement required
= 0.165 / 1+2+4
= 0.0235 m3 (cubic meter)
1 m3 = 30 bags
0.0235 m3 = ?
0.0235 x 30 bags = 0.705 bags
Quantity of lime required
= 0.0235 x 2
= 0.047 m3
1 m3 = 30 bags
0.047 m3 = ?
0.047 x 30 bags = 1.41 bags say 2 bags
Quantity of sand required
= 0.0235 x 4
=0.094 m3
Moziace tile flooring
Size of tile = 20 cm x 20 cm
Thickness of lime base = 20 mm
Proportion of mortar = ( 1 : 2 : 4 )
kitchen room ( 2.50 meter x 3.00 meter )
Area of one tile = 20 cm x 20 cm
Area of one tile = 400 cm
Area of one tile = 0.04 m2
Therefore, no. of tiles required = 2.50 x 3.00 / 0.04
No. of tiles required = 7.5/0.04
No. of tiles required = 187.5 nos. say 188 tiles
Proportion of mortar (1:2:4)
Thickness of lime base = 20 mm
Volume of lime base = Area of room x Thickness of lime base
Volume of lime base = 7.5 x (20mm/1000)……..(convert mm into meter)
Volume of lime base = 7.5 x 0.02
Volume of lime base = 0.15 m3 (cubic meter)
Considering 25 % more due to losses
= 0.15 + [0.15 x (25/100)]
= 0.187 m3 (cubic meter)
Proportion of mortar (1:2:4)
Quantity of cement required
= 0.187 / 1+2+4
= 0.0267 m3 (cubic meter)
1 m3 = 30 bags
0.0267 m3 = ?
0.0267 x 30 bags = 0.801 bags
Quantity of lime required
= 0.0267 x 2
= 0.0534 m3
1 m3 = 30 bags
0.0534 m3 = ?
0.0534 x 30 bags = 1.6 bags say 2 bags
Quantity of sand required
= 0.0267 x 4
=0.1068 m3
Moziace tile flooring
Size of tile = 20 cm x 20 cm
Thickness of lime base = 20 mm
Proportion of mortar = ( 1 : 2 : 4 )
Verandha (passage) ( 5.70 meter x 2.50 meter )
Area of one tile = 20 cm x 20 cm
Area of one tile = 400 cm
Area of one tile = 0.04 m2
Therefore, no. of tiles required = 2.50 x 3.00 / 0.04
No. of tiles required = 14.25/0.04
No. of tiles required = 356.25 nos. say 357 tiles
Proportion of mortar (1:2:4)
Thickness of lime base = 20 mm
Volume of lime base = Area of room x Thickness of lime base
Volume of lime base = 14.25 x (20mm/1000)……..(convert mm into meter)
Volume of lime base = 14.25x 0.02
Volume of lime base = 0.285 m3 (cubic meter)
Considering 25 % more due to losses
= 0.285 + [0.285 x (25/100)]
= 0.356 m3 (cubic meter)
Proportion of mortar (1:2:4)
Quantity of cement required
= 0.356 / 1+2+4
= 0.0508 m3 (cubic meter)
1 m3 = 30 bags
0.0508 m3 = ?
0.0508 x 30 bags = 1.52 bags
Quantity of lime required
= 0.0508 x 2
= 0.101 m3
1 m3 = 30 bags
0.101 m3 = ?
0.101 x 30 bags = 3.04 bags say 4 bags
Quantity of sand required
= 0.0508 x 4
=0.203 m3
Moziace tile flooring
Size of tile = 20 cm x 20 cm
Thickness of lime base = 20 mm
Proportion of mortar = ( 1 : 2 : 4 )
Bed room ( 5.00 meter x 3.60 meter )
Area of one tile = 20 cm x 20 cm
Area of one tile = 400 cm
Area of one tile = 0.04 m2
Therefore, no. of tiles required = 5.00 x 3.60 / 0.04
No. of tiles required = 18/0.04
No. of tiles required = 450 tiles
Proportion of mortar (1:2:4)
Thickness of lime base = 20 mm
Volume of lime base = Area of room x Thickness of lime base
Volume of lime base = 18 x (20mm/1000)……..(convert mm into meter)
Volume of lime base = 18 x 0.02
Volume of lime base = 0.36 m3 (cubic meter)
Considering 25 % more due to losses
= 0.36 + [0.36 x (25/100)]
= 0.45 m3 (cubic meter)
Proportion of mortar (1:2:4)
Quantity of cement required
= 0.45 / 1+2+4
= 0.064 m3 (cubic meter)
1 m3 = 30 bags
0.064 m3 = ?
0.064 x 30 bags = 1.92 say 2 bags
Quantity of lime required
= 0.064 x 2
= 0.128 m3
1 m3 = 30 bags
0.128 m3 = ?
0.128 x 30 bags = 3.84 bags say 4 bags
Quantity of sand required
= 0.064 x 4
=0.256 m3
Moziace tile flooring
Size of tile = 20 cm x 20 cm
Thickness of lime base = 20 mm
Proportion of mortar = ( 1 : 2 : 4 )
Hall (seating) room ( 5.70 meter x 4.10 meter )
Area of one tile = 20 cm x 20 cm
Area of one tile = 400 cm
Area of one tile = 0.04 m2
Therefore, no. of tiles required = 5.70 x 4.10 / 0.04
No. of tiles required = 23.37/0.04
No. of tiles required = 584.25 tiles say 585 tiles
Proportion of mortar (1:2:4)
Thickness of lime base = 20 mm
Volume of lime base = Area of room x Thickness of lime base
Volume of lime base = 23.37 x (20mm/1000)……..(convert mm into meter)
Volume of lime base = 23.37 x 0.02
Volume of lime base = 0.467 m3 (cubic meter)
Considering 25 % more due to losses
= 0.467 + [0.467 x (25/100)]
= 0.583 m3 (cubic meter)
Proportion of mortar (1:2:4)
Quantity of cement required
= 0.583 / 1+2+4
= 0.0832 m3 (cubic meter)
1 m3 = 30 bags
0.0832 m3 = ?
0.0832 x 30 bags = 2.49 say 3 bags
Quantity of lime required
= 0.0832 x 2
= 0.166 m3
1 m3 = 30 bags
0.166 m3 = ?
0.166 x 30 bags = 4.98 bags say 5 bags
Quantity of sand required
= 0.0832 x 4
=0.332 m3
Moziace tile flooring
Size of tile = 20 cm x 20 cm
Thickness of lime base = 20 mm
Proportion of mortar = ( 1 : 2 : 4 )
Enterance Hall room ( 4.20 meter x 3.00 meter )
Area of one tile = 20 cm x 20 cm
Area of one tile = 400 cm
Area of one tile = 0.04 m2
Therefore, no. of tiles required = 4.20 x 3.00 / 0.04
No. of tiles required = 12.6/0.04
No. of tiles required = 315 tiles
Proportion of mortar (1:2:4)
Thickness of lime base = 20 mm
Volume of lime base = Area of room x Thickness of lime base
Volume of lime base = 12.6 x (20mm/1000)……..(convert mm into meter)
Volume of lime base = 12.6 x 0.02
Volume of lime base = 0.252 m3 (cubic meter)
Considering 25 % more due to losses
= 0.252 + [0.252 x (25/100)]
= 0.315 m3 (cubic meter)
Proportion of mortar (1:2:4)
Quantity of cement required
= 0.315 / 1+2+4
= 0.045 m3 (cubic meter)
1 m3 = 30 bags
0.045 m3 = ?
0.045 x 30 bags = 1.35 say 2 bags
Quantity of lime required
= 0.045 x 2
= 0.09 m3
1 m3 = 30 bags
0.09 m3 = ?
0.09 x 30 bags = 2.7 bags say 3 bags
Quantity of sand required
= 0.045 x 4
=0.18 m3
Moziace tile flooring
Size of tile = 20 cm x 20 cm
Thickness of lime base = 20 mm
Proportion of mortar = ( 1 : 2 : 4 )
Bed room ( 3.60 meter x 5.00 meter )
Area of one tile = 20 cm x 20 cm
Area of one tile = 400 cm
Area of one tile = 0.04 m2
Therefore, no. of tiles required = 3.60 x 5.00 / 0.04
No. of tiles required = 18/0.04
No. of tiles required = 450 tiles
Proportion of mortar (1:2:4)
Thickness of lime base = 20 mm
Volume of lime base = Area of room x Thickness of lime base
Volume of lime base = 18 x (20mm/1000)……..(convert mm into meter)
Volume of lime base = 18 x 0.02
Volume of lime base = 0.36 m3 (cubic meter)
Considering 25 % more due to losses
= 0.36 + [0.36 x (25/100)]
= 0.45 m3 (cubic meter)
Proportion of mortar (1:2:4)
Quantity of cement required
= 0.45 / 1+2+4
= 0.064 m3 (cubic meter)
1 m3 = 30 bags
0.064 m3 = ?
0.064 x 30 bags = 1.92 say 2 bags
Quantity of lime required
= 0.064 x 2
= 0.128 m3
1 m3 = 30 bags
0.128 m3 = ?
0.128 x 30 bags = 3.84 bags say 4 bags
Quantity of sand required
= 0.064 x 4
=0.256 m3
Ceramic tile flooring
Floor tile size = 20 cm x 20 cm
Dado tile size = 15 cm x 20 cm
Proportion of mix = ( 1 : 2 : 4 )
Thickness of base = 20 mm
W.C ( 1.75 meter x 0.90 meter )
Floor tile
Area of one tile = 20 cm x 20 cm
Area of one tile = 400 cm
Area of one tile = 0.04 m2
Total no. of tiles required = W.C. floor area / Area of one tile
Total no. of tiles required = (1.75 x 0.90) / 0.04
Total no. of tiles required = 1.575 / 0.04
Total no. of tiles required = 39.37 say 40 tiles
Proportion of mix (1:2:4)
Thickness of base = 20 mm
Volume of base = Area of w.c. x Thickness of base
Volume of base = 1.575 x 0.02
Volume of base = 0.0315 m3 (cubic meter)
Considering 25 % more due to losses
= 0.0315 + [ 0.0315 x (25/100)]
= 0.0393 m3 (cubic meter)
Proportion of mortar (1:2:4)
Quantity of cement required = 0.0393 / 1+2+4
Quantity of cement required = 0.00561 m3 (cubic meter)
1 m3 = 30 bags
0.00561 m3 = ?
0.0561 x 30 bags = 0.168 bags
Quantity of lime required
= 0.00561 x 2
= 0.0112 m3 (cubic meter)
1 m3 = 30 bags
0.0112 m3 = ?
0.0112 x 30 = 0.336 m3 (cubic meter)
Quantity of sand required
= 0.00561 x 4
= 0.0224 m3 (cubic meter)
Dado for W.C.
12 mm thick (1:3) cement coarse sand mortar neat cement finished.
W.C. wall area for dado
( 1.75 x 2 + 0.90 x 2 ) x 3 – V – D2 [where v = ventilation, D2 = door]
15.9 – ( 0.75 x 0.90 ) – ( 0.75 x 2.10 )
15.9 – 0.675 – 1.575
= 12.75 m2
W.C. dado tile size = 15 cm x 20 cm
Area of one tile = 15 cm x 20 cm
Area of one tile = 300 cm2
Area of one tile = 3 m2 (in meter square)
Total no. of tile required = w.c. wall area / area of one tile in cubic meter
Total no. of tile required = 12.75 / 0.3
Total no. of tile required = 42.5 say 43 tiles
Proportion of mortar (1:3)
Thickness of base 12 mm
Volume of base = Area of wall (w.c.) x Thickness of base
Volume of base = 12.75 x (12/1000)
Volume of base = 0.153 m3 (cubic meter)
Considering 25 % more due to losses
0.153 + [ 0.153 x (25/100) ]
= 0.191 m3 (cubic meter)
Quantity of cement required
= 0.192 / 1+3
= 0.192 / 4
= 0.0477 m3 (cubic meter)
1 m3 = 30 bags
0.0477 m3 = ?
0.0477 x 30 bags = 1.43 say 2 bags
Quantity of sand required
= 0.0477 x 3
= 0.143 m3
Ceramic tile flooring
Floor tile size = 20 cm x 20 cm
Dado tile size = 15 cm x 20 cm
Proportion of mix = ( 1 : 2 : 4 )
Thickness of base = 20 mm
Bath room ( 2.60 meter x 1.00 meter )
Floor tile
Area of one tile = 20 cm x 20 cm
Area of one tile = 400 cm
Area of one tile = 0.04 m2
Total no. of tiles required = W.C. floor area / Area of one tile
Total no. of tiles required = (2.60 x 1.00) / 0.04
Total no. of tiles required = 2.60 / 0.04
Total no. of tiles required = 65 tiles
Proportion of mix (1:2:4)
Thickness of base = 20 mm
Volume of base = Area of Bathroom x Thickness of base
Volume of base = ( 2.60 x 1.00 ) x 20/1000 ……convert mm in meter
Volume of base = 0.052 m3 (cubic meter)
Considering 25 % more due to losses
= 0.052 + [ 0.052 x (25/100)]
= 0.065 m3 (cubic meter)
Proportion of mortar (1:2:4)
Quantity of cement required = 0.065 / 1+2+4
Quantity of cement required = 0.00928 m3 (cubic meter)
1 m3 = 30 bags
0.00928 m3 = ?
0.00928 x 30 bags = 0.278 bags
Quantity of lime required
= 0.00928 x 2
= 0.01856 m3 (cubic meter)
1 m3 = 30 bags
0.01856 m3 = ?
0.01856 x 30 = 0.55 bags
Quantity of sand required
= 0.00928 x 4
= 0.03712 m3 (cubic meter)
Dado for Bathroom
12 mm thick (1:3) cement coarse sand mortar neat cement finished.
W.C. wall area for dado
( 2.60 x 2 + 1 x 2 ) x 3 m – D2 – V – V1 [where v,v1= ventilation, D2 = door]
21.6 – ( 0.75 x 2.10 ) – ( 0.75 x 0.90 ) – ( 1.20 x 1.20 )
21.6 – 1.575 – 0.675 – 1.44
= 17.90 m2
Bathroom dado tile size = 15 cm x 20 cm
Area of one tile = 15 cm x 20 cm
Area of one tile = 300 cm2
Area of one tile = 0.3 m2 (in meter square)
Total no. of tile required = Bathroom wall area / area of one tile in square meter
Total no. of tile required = 17.91 / 0.3
Total no. of tile required = 59.7 say 60 tiles
Proportion of mortar (1:3)
Thickness of base 12 mm
Volume of base = Area of wall (bathroom) x Thickness of base
Volume of base = 17.91 x (12/1000)
Volume of base = 0.214 m3 (cubic meter)
Considering 25 % more due to losses
0.214 + [ 0.214 x (25/100) ]
= 0.267 m3 (cubic meter)
Quantity of cement required
= 0.267 / 1+3
= 0.267 / 4
= 0.066 m3 (cubic meter)
1 m3 = 30 bags
0.066 m3 = ?
0.066 x 30 bags = 2 bags
Quantity of sand required
= 0.066 x 3
= 0.198 m3
