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U.C.R. Masonry Quantity
Material required – cement, sand, stone etc.
Unit of measurement – m3 (cubic meter)
Mortar proportion –( 1 : 6 )
U.C.R. Masonry
Actual length of masonry wall
= (23.1 x 2 + 21.6 x 2) – 3 meter …..(deduction for gate)
= 89.4 – 3
= 86.4 meter
Consider 1 meter breath or width of U.C.R. Masonry. Height of U.C.R. Masonry wall is 3 meter.
Therefore, U.C.R. Masonry wall size is = L X B X H
Therefore size of U.C.R. Masonry wall = 86.4 x 1 x 3 meter (volume)
Stone required = 259.2 m3
Requirement of stone for U.C.R. Masonry wall is more 125 % of actual stone masonry volume.
Therefore, stone required = (125/100) x 259.2 m3
Therefore, stone required = 324 m3
Requirement of dry mortar for U.C.R. Masonry is 42 % of actual stone masonry volume.
Quantity of dry mortar required = 324 x (42/100) = 136.08 m3
Mortar Proportion ( 1 : 6 )
Quantity of cement required = 136.08/1+6
Quantity of cement required = 19.44 m3
1 m3 = 30 bags
19.44 m3 = ?
19.44 x 30 = 583.2 bags say 584 bags
Quantity of sand required
19.44 x 6 = 116.64 m3
Plinth Protection
Rubble soling & P.C.C. ( 1 : 3 : 6 )
Plinth protection upto 1 m width
Rubble soling
Stone required for rubble soling is –
Total length for rubble soling (as per drawing)
13.60 + 12.80 + 11.80 + 3.9 + 5.3 + 3.3 + 6.2
= 56.9 meter
Consider 1 m breadth for rubble soling
Therefore, total area of rubble soling = 56.9 m x 1 m = 56.9 m2
Therefore actual stone required for rubble soling is = 56.9 m3
Plinth protection for building with rubble soling pcc (1:3:6)
Consider 4 inch thick pcc (1:3:6) with 1 inch slop.
Volume of pcc (1:3:6) = Area of P.C.C. X Thickness of P.C.C.
Volume of pcc (1:3:6) = 56.9 m2 x 4 inch
Volume of pcc (1:3:6) = 56.9 x 0.0157
Volume of pcc (1:3:6) = 0.896 m3
Consider 25 % more due to losses.
Therefore, volume of P.C.C = 0.896 + ( 0.896 x 25/100 )
volume of P.C.C = 1.12 m3
P.C.C. ( 1 : 3 : 6 )
Quantity of cement required = 1.12 / 1+3+6 = 0.112 m3
1 m3 = 30 bags
0.112 m3 = ?
Therefore 0.112 x 30 bags = 3.36 bags say 4 bags
Quantity of sand required
0.112 x 3 = 0.336 m3
Quantity of aggregate required
0.112 x 6 = 0.672 m3
