Given:
Dia. Of bar = 12 mm
Clear cover = 25 mm
Clear span = 5000 mm
Slab thickness = 200 mm
Ld = 40 d
“D” = slab thickness – ( 2 x
clear cover ) – ( dia. Of bar )
= 200 – ( 2 x 25 ) – ( 10 )
= 138 mm
Cutting length
Clear span of slab + (2 x Ld) +
(2 x 0.42 D) – (1d x 4) – (2d x 2)
= 5000 + (2 x 40 x 12) + (2 x
0.42 x 138) – (1 x 12 x 4) – (2 x 12 x 2)
= 5980 mm
= 5.98 meter
