How to make bar bending schedule of beam reinforcement?

TYPE - 1

BBS CALCULATION

BOTTOM			TOP			STIRRUPS
Left	Mid	Right	Left	Mid	Right
2 – 25 ф + 2- 20 ф	2 – 25 ф + 2- 20 ф	2 – 25 ф + 2- 20 ф	2- 20 ф	2- 20 ф	2- 20 ф	8 ф @ 100, 150, 100 c/c

BOTTOM BAR

Development length = 50d

1^st layer

25 ф = length of beam + development length – bend

= 5000 + (50 x 25 x 2) – (2 x 25 x 1 x 2)

= 7400 mm

= 7.4 meter

For 2 nos. = 7.4 x 2 = 14.8 meter

2^nd layer

20 ф = length of beam + development length – bend

= 5000 + (50 x 20 x 2) – (2 x 20 x 1 x 2)

= 6920 mm

= 6.92 meter

For 2 nos. = 6.92 x 2 = 13.84 meter

TOP BAR

20 ф = same as 2^nd layer of bottom bar

= 13.84 meter

STIRRUPS

For zone – 1

L/3 = 5000/3 = 1666.67 mm

No. of stirrups = (Length / Spacing) + 1

= (1666.67 / 100) + 1

= 17.7 say 18 nos.

Total no. of stirrups for zone 1 = 18 x 2 = 36 nos.

For zone – 2

No. of stirrups = (Length / Spacing) - 1

= (1666.67 / 150) - 1

= 10 nos.

Therefor total = 36 + 1 = 46 nos.

Cutting length of stirrups

a= 300 – (2 x clear cover) – (2 x half of bar)

a= 300 – (2 x 30) – (2 x 4)

a= 232 mm

b= 600 – (2 x clear cover) – (2 x half of bar)

b= 600 – (2 x 30) – (2 x 4)

b= 532 mm

cutting length = (2 x a) + (2 x b) + (2 x 10d) – (3 x d x 2) – (2d x 3)

= (2 x 232) + (2 x 532) + (2 x 10 x 8) – (3 x 8 x 2) – (2 x 8 x 3)

= 1592 mm

= 1.592 meter

For 46 stirrups = 1.592 x 46 = 73.23 meter

Note:

For bend

45 degree = 1d

90 degree = 2d

135 degree = 3d