SCHEDULE OF OPENINGS
SR. NO. | ITEM | DIAMENSION’S |
D | DOOR | 1.20 M X 2.10 M |
D1 | DOOR | 0.90 M X 2.10 M |
D2 | DOOR | 0.75 M X 2.10 M |
W | WINDOW | 1.20 M X 1.20 M |
V | VENTILATION | 0.75 M X 0.90 M |
V1 | VENTILATION | 1.20 M X 1.20 M |
Internal Plastering
Store room (2.20 meter x 3.00 meter )
Plastering thickness = 12 mm
Calculation of area of walls for plaster.
Actual area of walls – deduction of openings (i.e window, door, ventilation)
Actual area of wall = (2.20 x 2 + 3 x 2) x 3 – W – W – D1
= (4.4 + 6) x 3 – (1.20 x 1.20) – (1.20 x 1.20) – (0.90 x 2.10)
= 31.2 – 1.44 – 1.44 – 1.89
= 26.43 m2 …..(square meter)
Plastering mortar proportion ( 1 : 4 )
Plastering thickness = 12 mm
Volume of plaster = Actual Area of wall x Thickness of plaster
Volume of plaster = 26.43 x (12/1000)
Volume of plaster = 0.317 m3 …….(cubic meter)
30 % Extra wet mortar is required for filling up joints in masonry and uneven surface.
Volume of mortar required = 0.317 + [0.317 x (30/100)]
Volume of mortar required = 0.412 m3 ………(cubic meter)
Dry volume is 25 % more than wet volume.
Therefore, Dry volume required = 0.412 + [0.412 x (25/100)]
Dry volume of mortar = 0.515 m3 ………(cubic meter)
Required quantity of cement = dry vol. of mortar / mortar proportion
= 0.515 / 1+4
= 0.515 / 5
= 0.103 m3 ……(cubic meter)
1 m3 = 30 bags
0.103 m3 = ?
Therefore, Cement in bags = 0.103 x 30 = 3.09 say 4 bags
Sand required
= 0.103 x 4
= 0.412 m3
= 0.412 / 2.83 …….(convert m3 into brass)
= 0.145 brass
Internal Plastering
Kitchen room (2.50 meter x 3.00 meter )
Plastering thickness = 12 mm
Calculation of area of walls for plaster.
Actual area of walls – deduction of openings (i.e window, door, ventilation)
Actual area of wall = (2.50 x 2 + 3.00 x 2) x 3 – W – D1 – D1
= (5 + 6) x 3 – (1.20 x 1.20) – (1.20 x 2.10) - (1.20 x 2.10
= 33 – 1.44 – 2.52 – 2.52
= 26.52 m2 …..(square meter)
Plastering mortar proportion ( 1 : 4 )
Plastering thickness = 12 mm
Volume of plaster = Actual Area of wall x Thickness of plaster
Volume of plaster = 26.52 x (12/1000)
Volume of plaster = 0.318 m3 …….(cubic meter)
30 % Extra wet mortar is required for filling up joints in masonry and uneven surface.
Volume of mortar required = 0.318 + [0.317 x (30/100)]
Volume of mortar required = 0.413 m3 ………(cubic meter)
Dry volume is 25 % more than wet volume.
Therefore, Dry volume required = 0.413 + [0.413 x (25/100)]
Dry volume of mortar = 0.516 m3 ………(cubic meter)
Required quantity of cement = dry vol. of mortar / mortar proportion
= 0.516 / 1+4
= 0.516 / 5
= 0.103 m3 ……(cubic meter)
1 m3 = 30 bags
0.103 m3 = ?
Therefore, Cement in bags = 0.103 x 30 = 3.09 say 4 bags
Sand required
= 0.516 x 4
= 2.06 m3
= 2.06 / 2.83 …….(convert m3 into brass)
= 0.727 brass
Internal Plastering
Verandha (Passage) (5.70 meter x 2.50 meter )
Plastering thickness = 12 mm
Calculation of area of walls for plaster.
Actual area of walls – deduction of openings (i.e window, door, ventilation)
Actual area of wall = (5.70 x 2 + 2.50 x 2) x 3 – W – D1 – D
= (11.4 + 5) x 3 – (1.20 x 1.20) – (0.90 x 2.10) – (1.20 x 2.10)
= 49.2 – 1.44 – 1.89 – 2.52
= 43.35 m2 …..(square meter)
Plastering mortar proportion ( 1 : 4 )
Plastering thickness = 12 mm
Volume of plaster = Actual Area of wall x Thickness of plaster
Volume of plaster = 43.25 x (12/1000)
Volume of plaster = 0.520 m3 …….(cubic meter)
30 % Extra wet mortar is required for filling up joints in masonry and uneven surface.
Volume of mortar required = 0.520 + [0.520 x (30/100)]
Volume of mortar required = 0.676 m3 ………(cubic meter)
Dry volume is 25 % more than wet volume.
Therefore, Dry volume required = 0.676 + [0.676 x (25/100)]
Dry volume of mortar = 0.845 m3 ………(cubic meter)
Required quantity of cement = dry vol. of mortar / mortar proportion
= 0.845 / 1+4
= 0.845 / 5
= 0.169 m3 ……(cubic meter)
1 m3 = 30 bags
0.169 m3 = ?
Therefore, Cement in bags = 0.169 x 30 = 5.07 say 6 bags
Sand required
= 0.845 x 4
= 3.38 m3
= 3.38 / 2.83 …….(convert m3 into brass)
= 1.19 brass
Internal Plastering
Bed room (5.00 meter x 3.60 meter )
Plastering thickness = 12 mm
Calculation of area of walls for plaster.
Actual area of walls – deduction of openings (i.e window, door, ventilation)
Actual area of wall = (5.00 x 2 + 3.60 x 2) x 3 – W – W – D2 – D
= (10 + 7.2) x 3 – (1.20 x 1.20) – (1.20 x 1.20) - (0.75 x 2.10) – (1.20 x 2.10)
= 51.6 – 1.44 – 1.44 - 1.575 – 2.52
= 44.625 m2 …..(square meter)
Plastering mortar proportion ( 1 : 4 )
Plastering thickness = 12 mm
Volume of plaster = Actual Area of wall x Thickness of plaster
Volume of plaster = 44.625 x (12/1000)
Volume of plaster = 5.355 m3 …….(cubic meter)
30 % Extra wet mortar is required for filling up joints in masonry and uneven surface.
Volume of mortar required = 5.355 + [5.335 x (30/100)]
Volume of mortar required = 6.96 m3 ………(cubic meter)
Dry volume is 25 % more than wet volume.
Therefore, Dry volume required = 6.96 + [6.96 x (25/100)]
Dry volume of mortar = 8.7 m3 ………(cubic meter)
Required quantity of cement = dry vol. of mortar / mortar proportion
= 8.7 / 1+4
= 8.7 / 5
= 1.74 m3 ……(cubic meter)
1 m3 = 30 bags
1.74 m3 = ?
Therefore, Cement in bags = 1.74 x 30 = 52.2 say 53 bags
Sand required
= 8.7 x 4
= 34.8 m3
= 34.8 / 2.83 …….(convert m3 into brass)
= 12.29 brass
Internal Plastering
Sitting room (5.70 meter x 4.10 meter )
Plastering thickness = 12 mm
Calculation of area of walls for plaster.
Actual area of walls – deduction of openings (i.e window, door, ventilation)
Actual area of wall = (5.70 x 2 + 4.10 x 2) x 3 – W – W - W – D – D - D
= (11.4 + 8.2) x 3 – (1.20 x 1.20) – (1.20 x 1.20) – (1.20 x 1.20) - (1.20 x 2.10) - (1.20 x 2.10) - (1.20 x 2.10)
= 58.8 – 1.44 – 1.44 - 1.44 – 2.52 – 2.52 – 2.52
= 46.92 m2 …..(square meter)
Plastering mortar proportion ( 1 : 4 )
Plastering thickness = 12 mm
Volume of plaster = Actual Area of wall x Thickness of plaster
Volume of plaster = 46.92 x (12/1000)
Volume of plaster = 5.63 m3 …….(cubic meter)
30 % Extra wet mortar is required for filling up joints in masonry and uneven surface.
Volume of mortar required = 5.63 + [5.63 x (30/100)]
Volume of mortar required = 7.31 m3 ………(cubic meter)
Dry volume is 25 % more than wet volume.
Therefore, Dry volume required = 7.31 + [7.31 x (25/100)]
Dry volume of mortar = 9.13 m3 ………(cubic meter)
Required quantity of cement = dry vol. of mortar / mortar proportion
= 9.13 / 1+4
= 9.13 / 5
= 1.82 m3 ……(cubic meter)
1 m3 = 30 bags
1.82 m3 = ?
Therefore, Cement in bags = 1.82 x 30 = 54.78 say 55 bags
Sand required
= 9.13 x 4
= 36.52 m3
= 36.52 / 2.83 …….(convert m3 into brass)
= 12.90 brass
Internal Plastering
Enterance hall (4.20 meter x 3.00 meter )
Plastering thickness = 12 mm
Calculation of area of walls for plaster.
Actual area of walls – deduction of openings (i.e window, door, ventilation)
Actual area of wall = (4.20 x 2 + 3.00 x 2) x 3 – W – W – D – D - D
= (8.4 + 6) x 3 – (1.20 x 1.20) – (1.20 x 1.20) - (1.20 x 2.10) - (1.20 x 2.10) - (1.20 x 2.10)
= 43.2 – 1.44 – 1.44 – 2.52 – 2.52 – 2.52
= 32.76 m2 …..(square meter)
Plastering mortar proportion ( 1 : 4 )
Plastering thickness = 12 mm
Volume of plaster = Actual Area of wall x Thickness of plaster
Volume of plaster = 32.76 x (12/1000)
Volume of plaster = 3.93 m3 …….(cubic meter)
30 % Extra wet mortar is required for filling up joints in masonry and uneven surface.
Volume of mortar required = 3.93 + [3.93 x (30/100)]
Volume of mortar required = 5.10 m3 ………(cubic meter)
Dry volume is 25 % more than wet volume.
Therefore, Dry volume required = 5.10 + [5.10 x (25/100)]
Dry volume of mortar = 6.37 m3 ………(cubic meter)
Required quantity of cement = dry vol. of mortar / mortar proportion
= 6.37 / 1+4
= 6.37 / 5
= 1.27 m3 ……(cubic meter)
1 m3 = 30 bags
1.27 m3 = ?
Therefore, Cement in bags = 1.27 x 30 = 38.1 say 39 bags
Sand required
= 1.27 x 4
= 5.08 m3
= 5.08 / 2.83 …….(convert m3 into brass)
= 1.79 brass
Internal Plastering
Bed room (3.60 meter x 5.00 meter )
Plastering thickness = 12 mm
Calculation of area of walls for plaster.
Actual area of walls – deduction of openings (i.e window, door, ventilation)
Actual area of wall = (3.60 x 2 + 5.00 x 2) x 3 – W – W - W – D – D2
= (7.2 + 10) x 3 – (1.20 x 1.20) – (1.20 x 1.20) - (1.20 x 1.20) - (1.20 x 2.10) – (0.75 x 2.10)
= 51.6 – 1.44 – 1.44 – 1.44 - 2.52 – 1.575
= 43.18 m2 …..(square meter)
Plastering mortar proportion ( 1 : 4 )
Plastering thickness = 12 mm
Volume of plaster = Actual Area of wall x Thickness of plaster
Volume of plaster = 43.18 x (12/1000)
Volume of plaster = 5.18 m3 …….(cubic meter)
30 % Extra wet mortar is required for filling up joints in masonry and uneven surface.
Volume of mortar required = 5.18 + [5.18 x (30/100)]
Volume of mortar required = 6.73 m3 ………(cubic meter)
Dry volume is 25 % more than wet volume.
Therefore, Dry volume required = 6.73 + [6.73 x (25/100)]
Dry volume of mortar = 8.41 m3 ………(cubic meter)
Required quantity of cement = dry vol. of mortar / mortar proportion
= 8.41 / 1+4
= 8.41 / 5
= 1.68 m3 ……(cubic meter)
1 m3 = 30 bags
1.68 m3 = ?
Therefore, Cement in bags = 1.68 x 30 = 50.4 say 51 bags
Sand required
= 8.41 x 4
= 33.64 m3
= 33.64 / 2.83 …….(convert m3 into brass)
= 11.88 brass
Internal Plastering
Bath room (2.60 meter x 1.00 meter )
Plastering thickness = 12 mm
Calculation of area of walls for plaster.
Actual area of walls – deduction of openings (i.e window, door, ventilation)
Actual area of wall = (2.60 x 2 + 1.00 x 2) x 3 – V – V1 - D2
= (5.20 + 2) x 3 – (0.75 x 0.90) – (1.20 x 1.20) - (0.75 x 2.10)
= 15.9 – 0.675 – 1.44 - 1.575
= 12.21 m2 …..(square meter)
Plastering mortar proportion ( 1 : 4 )
Plastering thickness = 12 mm
Volume of plaster = Actual Area of wall x Thickness of plaster
Volume of plaster = 12.21 x (12/1000)
Volume of plaster = 1.46 m3 …….(cubic meter)
30 % Extra wet mortar is required for filling up joints in masonry and uneven surface.
Volume of mortar required = 1.46 + [1.46 x (30/100)]
Volume of mortar required = 1.89 m3 ………(cubic meter)
Dry volume is 25 % more than wet volume.
Therefore, Dry volume required = 1.89 + [1.89 x (25/100)]
Dry volume of mortar = 2.36 m3 ………(cubic meter)
Required quantity of cement = dry vol. of mortar / mortar proportion
= 2.36 / 1+4
= 2.36 / 5
= 0.472 m3 ……(cubic meter)
1 m3 = 30 bags
0.472 m3 = ?
Therefore, Cement in bags = 0.472 x 30 = 14.17 say 15 bags
Sand required
= 2.36 x 4
= 9.45 m3
= 9.45 / 2.83 …….(convert m3 into brass)
= 3.33 brass
Internal Plastering
W.C. (1.75 meter x 0.90 meter )
Plastering thickness = 12 mm
Calculation of area of walls for plaster.
Actual area of walls – deduction of openings (i.e window, door, ventilation)
Actual area of wall = (1.75 x 2 + 0.90 x 2) x 3 – V1 - D2
= (3.5 + 1.8) x 3 – (1.20 x 1.20) - (0.75 x 2.10)
= 15.9 – 1.44 - 1.575
= 12.89 m2 …..(square meter)
Plastering mortar proportion ( 1 : 4 )
Plastering thickness = 12 mm
Volume of plaster = Actual Area of wall x Thickness of plaster
Volume of plaster = 12.89 x (12/1000)
Volume of plaster = 1.54 m3 …….(cubic meter)
30 % Extra wet mortar is required for filling up joints in masonry and uneven surface.
Volume of mortar required = 1.54 + [1.54 x (30/100)]
Volume of mortar required = 2.002 m3 ………(cubic meter)
Dry volume is 25 % more than wet volume.
Therefore, Dry volume required = 2.002 + [2.002 x (25/100)]
Dry volume of mortar = 2.50 m3 ………(cubic meter)
Required quantity of cement = dry vol. of mortar / mortar proportion
= 2.50 / 1+4
= 2.50 / 5
= 0.5 m3 ……(cubic meter)
1 m3 = 30 bags
0.5 m3 = ?
Therefore, Cement in bags = 0.5 x 30 = 15 bags
Sand required
= 2.50 x 4
= 10 m3
= 10 / 2.83 …….(convert m3 into brass)
= 3.53 brass
