Find the quantity of earthwork of a canal cutting from chainage 30 to 90 with following details. Bed width = 10 M, Side slope 1:1.

Chainage in M
30
60
90
Depth of cutting in M
1.6
1.8
2.0

C/S at chainage 30 m.



C/S at chainage 60 m.



C/S at chainage 90 m.




C/S area for section 1
= Bd1 + Sd1 2
= 10 x 1.6 + 1 x 1.62
= 18.56 m2

C/S area for section 2
= Bd2 + Sd2 2
= 10 x 1.8 + 1 x 1.82
= 21,24 m2

C/S area for section 3
= Bd1 + Sd3 2
= 10 x 2 + 1 x 22
= 24 m2

Total earthwork between C/S 1 and C/S 2
= Mean area x Length
= [(18.56 + 21.24) / 2] x 30
= 597 m3

Total earthwork between C/S 2 and C/S 3
= Mean area x Length
= [(21.24 + 24.00) / 2] x 30
= 678.60 m3

Therefor total earthwork between chainage
30 to 90 = 597 + 678.60
               = 12775.60 m3