Find
the quantity of earthwork of a canal cutting from chainage 30 to 90 with
following details. Bed width = 10 M, Side slope 1:1.
Chainage
in M
|
30
|
60
|
90
|
Depth
of cutting in M
|
1.6
|
1.8
|
2.0
|
C/S at chainage 30 m.
C/S at chainage 60 m.
C/S at chainage 90 m.
C/S area for section 1
= Bd1 + Sd1 2
= 10 x 1.6 + 1 x 1.62
= 18.56 m2
C/S area for section 2
= Bd2 + Sd2 2
= 10 x 1.8 + 1 x 1.82
= 21,24 m2
C/S area for section 3
= Bd1 + Sd3 2
= 10 x 2 + 1 x 22
= 24 m2
Total earthwork between C/S 1
and C/S 2
= Mean area x Length
= [(18.56 + 21.24) / 2] x 30
= 597 m3
Total earthwork between C/S 2
and C/S 3
= Mean area x Length
= [(21.24 + 24.00) / 2] x 30
= 678.60 m3
Therefor total earthwork
between chainage
30 to 90 = 597 + 678.60
= 12775.60 m3